3 years ago

Find the slope of the line passing through the points (-1,3) and (4,-7

Mathematics

1 answer:

DanielleElmas [232]3 years ago

4 0

You use the slope formula:

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

m is the slope. Plug in the points.

m = $\frac{-7 - 3}{4 - (-1)}$

m = $\frac{-7 - 3}{4+1}$

m = $\frac{-10}{5}$

m = -2

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Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

BigorU [14]

For a moment, let $y=x^2-2x+5$ . Then by the distributive property,

$(2x^2+4x-3)p=2x^2p+4xp-3p$

Again by the distributive property,

$2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2$

$4xp=4x(x^2-2x+5)=4x^3-8x^2+20x$

$-3p=-3(x^2-2x+5)=-3x^2+6x-15$

Taking everything together, we get

$(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)$
$(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15$