The correct answer is B). 6
Radius of inscribed circle of triangle HJK is 6 unit
Step-by-step explanation:
As shown in figure,
The triangle HJK has In-circle or inscribed circle of radius PL(or PM or PN)
Since, PL and PM is radius of same in-circle,
PL = PM
Given that PL=3x+4 and PM =6x-14
3x+4=6x-14
3x=18
x=6
Thus, The correct answer is B). 6
Answer:
4
Step-by-step explanation:
my theory would be 4
The standard equation of a circle is expressed as
(x - h)^2 + (y - k)^2 = r^2
where
h is the x coordinate of the center of the circle
k is the y coordinate of the center of the circle
r is the radius of the circle(the distance from the center of the circle to the circumference
From the graph,
h = - 1
y = 4
r = 5
By substituting these values into the equation, we have
(x - - 1)^2 + (y - 4)^2 = 5^2
(x + 1)^2 + (y - 4)^2 = 25
Thus, the equation of the circle is
(x + 1)^2 + (y - 4)^2 = 25
Answer:
P= 3/13
Step-by-step explanation:
R=7
B=7
Total=14
P(one red marble)=7/14=1/2
P(another red marble no replacement)=6/13
1/2 times 6/13=6/26=3/13
