All categories

3 years ago

Find the slope of the line passing through the points (-1,3) and (4,-7

Mathematics

1 answer:

DanielleElmas [232]3 years ago

4 0

You use the slope formula:

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

m is the slope. Plug in the points.

m = $\frac{-7 - 3}{4 - (-1)}$

m = $\frac{-7 - 3}{4+1}$

m = $\frac{-10}{5}$

m = -2

You might be interested in

What is the slope of the line represented by y= x+ 9 PLZ HELP

sergiy2304 [10]

Answer:

1 is the slope

Step-by-step explanation:

When the equation of a line is written in the form

y = mx+b, m is the slope and b is the y intercept

y =x +9

y = 1x+9

1 is the slope and 9 is the y intercept

3 0

3 years ago

The x-intercepts and vertex of the quadratic relation y = –(x + 3)(x + 5) are:

baherus [9]

Answer:

d) x-intercepts are –3 and –5; vertex is (–4, 1)

Step-by-step explanation:

parabola are the vertex findings -4

we find these using formula m +n / 2

m+ n = -3 -5 / 2 = -4

m+n / 2 = -8/2 = -4

xv = -4

plug in -4 to find yv

(x+5)

(-4 + 5)

yv = 1

5 0

2 years ago

A thin metal plate, located in the xy-plane, has temperature T(x, y) at the point (x, y). Sketch some level curves (isothermals)

Sophie [7]

Answer:

Step-by-step explanation:

Given that:

$T(x,y) = \dfrac{100}{1+x^2+y^2}$

This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c

here c is the constant.

$c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)$

By cross multiply

$c({1+x^2+2y^2}) = 100$

$1+x^2+2y^2 = \dfrac{100}{c}$

$x^2+2y^2 = \dfrac{100}{c} - 1 \ \ -- (2)$

From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.

Now,

$\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1$

This is the equation for the family of the eclipses centred at (0,0) is :

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1$

$a^2 = \dfrac{100}{c} -1 \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}$

Therefore; the level of the curves are all the eclipses with the major axis:

$a = \sqrt{\dfrac{100 }{c}-1}$ and a minor axis $b = \sqrt{\dfrac{50 }{c}-\dfrac{1}{2}}$ which satisfies the values for which 0< c < 100.

The sketch of the level curves can be see in the attached image below.

7 0

3 years ago

9 × 2(3 + 5) – (10 × 12) = y

vagabundo [1.1K]

The answer is y=24 your welcome

5 0

2 years ago

How does a digit in the 10 thousand place compared toa digit in the 10 place

choli [55]

For example, in the number 14,509, fourteen thousand five hundred and nine, 1 is in the ten thousands place, and zero is in the tens place.

1 4, 5 0 9
ten thousand^ ten^

6 0

3 years ago