I couldn’t figure that one out as well but I picked 80 square feet
For this case we have a function of the form:
Where:
We must find the value of the function when, that is, . So:
We have to:
So:
Different signs are subtracted and the major sign is placed.
Answer:
So since x= sand bags replace x with 0 so 7y=105 is left divide by 7 and you get y=15 so 15 bags
Answer:
From the values obtained, we can see that after the initial 10mg/L values obtained in the first 1 and 2 minutes, the concentration has been dipping and it will continue to do so.
Step-by-step explanation:
The concentration monitored ar time, t > 0 is represented by :
C(t) = 30t / (t² + 2.)
At, t = 1
C(1) = 30(1) / (1 + 2) = 30/3 = 10
At t = 2
C(2) = 30(2) / (2² + 2) = 60/(4+2) = 60/6 = 10
At t = 3
C(3) = 30(3) / (3² + 2) = 90/ 11 = 8.18
At t = 4
C(4) = 30(4) / (4²+2) = 120/18 = 6.67
At t = 5
C(5) = 30(5) / (5²+2) = 150/ 27 = 5.55
At t = 10
C(10) = 30(10) / (10²+2) = 300/102 = 2.94
From the values obtained, we can see that after the initial 10mg/L values obtained in the first 1 and 2 minutes, the concentration has been dipping and it will continue to do so.