D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21
The answer is 3.14 m
The area (A) of the circle with radius r is: A = π · r²
The area of the quarter of the circle is: A1 = 1/4A = 1/4 · π · r²
We have:
A1 = ?
r = ?
π = 3.14
d = 4 m
A diameter d is the twice of the radius r: d = 2r.
Therefore, the radius is the half of the diameter: r = d/2
So, the area of the quarter circle would be:
A1 = 1/4 · π · r² = 1/4 · π · (d/2)² =1/4 · π · d²/2² = 1/4 · π · d²/4 = 1/16 · π · d²
A1 = 1/16 · π · d² = 1/16 · 3.14 · 4² = 1/16 · 3.14 · 16 = 3.14 m
Answer:
(A), (C) and (D).
Step-by-step explanation:
An equation will have infinite solutions if both sides of the equal sign are the exact same thing, for instance
. (You can test this with any value of x and find that they all work!)
So to find the equations that have infinite solutions, we need to see which have the same exact sides.
have the same thing on each side:
, so this has infinite solutions.
does not have the same thing on each side, so it doesn’t have infinite solutions (it has 1)
has the same thing on each side:
, so this has infinite solutions.
And finally,
has the same thing on each side:
, so it has infinite solutions.
Hope this helped!
So we always make the denominator (bottom number) the same, then when it’s the same we just add!