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ivanzaharov [21]
3 years ago
5

A smart phone plan has a monthly base fee that includes 5 gigabytes of data. An overage charge is applied when the data usage ex

ceed 5 gigabytes. The equation C = 59 + 15(g − 5) models the plan, where C represents the monthly cost, in dollars, and g represents the total number of gigabytes used for the month. What does the value 15 represent in the equation
A:The base fee per month, in dollars, for the plan

B: The cost, in dollars, for each additional gigabyte used.

C:The average cost, in dollars, for data usage per month.

D:The average data usage, in gigabytes, per month
Mathematics
2 answers:
ipn [44]3 years ago
8 0

Answer:

B. The cost, in dollars, for each additional gigabyte used.

Step-by-step explanation:

We are given that,

The equation modeled for the plan is, C=59+15(g-5).

Since, we have that,

<em>The plan has a monthly charge that includes 5 gigabytes of data and over-charge fee for gigabytes exceeding 5 gigabytes.</em>

Thus, when g= 5, C= 59, in dollars.

Also, when g> 5, C=59+15(g-5).

So, we get that,

The expression 15(g-5) represents the cost for the additional (g-5) gigabytes used.

Thus, 15 represents the cost, in dollars, for the additional gigabytes used.

Thus, option B is correct.

Flura [38]3 years ago
4 0

Answer:

B The cost, in dollars, for each additional gigabyte used.

Step-by-step explanation:

C = 59 + 15(g − 5)

when g=5, C=59 where it is the monthly cost

when g=6, c=59 +15, interpret that each additional gigabyte used will increase the cost for 15

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Answer:

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}  

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Step-by-step explanation:

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

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And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)

We don't have a prior estimation for the proportion \hat p so we can use 0.5 as an approximation for this case  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

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