<span>y=1/12(x-1)2<span>+4
attached is a file/ picture i made in google images of a graph of it, i explain the steps as well.
id appreciate a brainliest since the drawing took a good 15 minutes but its up to you! Hope i helped.</span></span>
<span>A)x-y+3 is your answer
Proof:
(5 x)/4 - 8 y - x/4 + 7 y + 3
Put each term in (5 x)/4 - 8 y - x/4 + 7 y + 3 over the common denominator 4: (5 x)/4 - 8 y - x/4 + 7 y + 3 = (5 x)/4 - (32 y)/4 - (x)/4 + (28 y)/4 + 12/4:
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4 = (5 x - 32 y - x + 28 y + 12)/4:
(5 x - 32 y - x + 28 y + 12)/4
Grouping like terms, 5 x - 32 y - x + 28 y + 12 = (28 y - 32 y) + (5 x - x) + 12:
((28 y - 32 y) + (5 x - x) + 12)/4
28 y - 32 y = -4 y:
(-4 y + (5 x - x) + 12)/4
5 x - x = 4 x:
(-4 y + 4 x + 12)/4
Factor 4 out of -4 y + 4 x + 12:
(4 (-y + x + 3))/4
(4 (-y + x + 3))/4 = 4/4×(3 + x - y) = 3 + x - y:
Answer: 3 + x - y
</span>
Answer:
a) 25 is 3 standard deviation from the mean
b) Is far away from the mean, only 0,3 % away from the right tail
c) 25 is pretty close to the mean (just a little farther from 1 standard deviation)
Step-by-step explanation:
We have a Normal Distribution with mean 16 in.
Case a) we also have a standard deviation of 3 inches
3* 3 = 9
16 (the mean) plus 3*σ equal 25 in. the evaluated value, then the value is 3 standard deviation from the mean
Case b) 25 is in the range of 99,7 % of all value, we can say that value is far away from the mean, considering that is only 0,3 % away from the right tail
Case c) If the standard deviation is 7 then
mean + 1*σ = 16 + 7 =23
25> 23
25 is pretty close to the mean only something more than 1 standard deviation
Answer:
-8,0
Step-by-step explanation:
From one end of a segment to the midpoint, it takes -6x to get to the midpoint. Based on that, you can go another 6 over the y graph and get -8 for x.
For y, the segment goes from 4 to 2 (a -2 over the x graph). you can infer then that the other end will be 0.
The answer is b, as angles ABC is the first half of the angle.