9514 1404 393
Answer:
see below
Step-by-step explanation:
We assume your functions are ...
f(x) = x²
g(x) = (x -4)² +12
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You need to be able to recognize that g(x) matches a pattern:
g(x) = f(x-h) +k
where h = 4, and k = 12.
In this pattern, the value of h is the number of units the graph is translated to the right. The value of k is the number of units the graph is translated up.
So, g(x) is the same as the graph of f(x), but translated 4 units right and 12 units up.
Answer:
12 + 2x = y
Step-by-step explanation:
y would be the total cost
Answer:
use this conversion table ==>
Step-by-step explanation:
KG / hG / daG / GRAMME / G / cG / mG
2 0 0 0
2 KG = 2000 grammes
Kg = kilogramme (1000 g)
hg = hectogramme (100 g)
daG = decagramme (10 g)
GRAMME = reference unit
cg = centigramme (0,1 g)
dG = décigramme (0,01 g)
mG= milligramme (0,001 g)
☺☺☺
Answer:
350
Step-by-step explanation:
The solution to the equation can be found by multiplying by the denominator, then dividing by its coefficient.
![0.22 = \dfrac{77}{x}\qquad\text{given}\\\\0.22x = 77\qquad\text{multiply by $x$}\\\\x=\dfrac{77}{0.22}=350\qquad\text{divide by the coefficient of x}](https://tex.z-dn.net/?f=0.22%20%3D%20%5Cdfrac%7B77%7D%7Bx%7D%5Cqquad%5Ctext%7Bgiven%7D%5C%5C%5C%5C0.22x%20%3D%2077%5Cqquad%5Ctext%7Bmultiply%20by%20%24x%24%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B77%7D%7B0.22%7D%3D350%5Cqquad%5Ctext%7Bdivide%20by%20the%20coefficient%20of%20x%7D)
The missing value in the fraction is 350.
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<em>Additional comment</em>
Here, we have rewritten the percentage as a decimal fraction. You could also rewrite it as a ratio of two integer: 22% = 22/100. Sometimes there is confusion about percentages. It can help to think of the % symbol as meaning /100:
22% = 22/100
Of course, that is "twenty-two hundredths" or 0.22.
If you just write the problem using 22/100 for 22%, then you get the proportion ...
22/100 = 77/x
22x = 7700 . . . . . "cross multiply" (multiply by 100x)
x = 7700/22 = 350 . . . . divide by the coefficient of x
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If you're paying attention, you see that the solution of this kind of equation has the appearance that the denominator variable and the left-side value are simply swapped:
![0.22 = \dfrac{77}{x}\ \leftrightarrow\ x=\dfrac{77}{0.22}](https://tex.z-dn.net/?f=0.22%20%3D%20%5Cdfrac%7B77%7D%7Bx%7D%5C%20%5Cleftrightarrow%5C%20x%3D%5Cdfrac%7B77%7D%7B0.22%7D)
Effectively, we have multiplied both sides of the equation on the left by x/0.22. There is a <em>property of equality</em> that lets us do that. There is no such thing as a property of equality that says "swap with denominator." You must always pay attention to what is allowed by the properties of equality.
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