f(x) = 7 is a even function
<em><u>Solution:</u></em>
Given that we have to find the even function
A function is even if and only if f(–x) = f(x)
<em><u>Steps to follow:</u></em>
Replace x with -x and compare the result to f(x). If f(-x) = f(x), the function is even.
If f(-x) = - f(x), the function is odd.
If f(-x) ≠ f(x) and f(-x) ≠ -f(x), the function is neither even nor odd.
<h3>Option 1</h3>
![f(x) = (x - 1)^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%201%29%5E2)
Substitute x = -x in above function
![f(-x) = (-x - 1)^2](https://tex.z-dn.net/?f=f%28-x%29%20%3D%20%28-x%20-%201%29%5E2)
Thus ![f(-x) \neq f(x)](https://tex.z-dn.net/?f=f%28-x%29%20%5Cneq%20f%28x%29)
So this is not a even function
<h3>Option 2</h3>
f(x) = 8x
Substitute x = -x in above function
f(-x) = 8(-x) = -8x
Thus ![f(-x) \neq f(x)](https://tex.z-dn.net/?f=f%28-x%29%20%5Cneq%20f%28x%29)
So this is not a even function
<h3>Option 3</h3>
![f(x) = x^2 - x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E2%20-%20x)
Substitute x = -x in above function
![f(-x) = (-x)^2 - (-x) = x^2 + x](https://tex.z-dn.net/?f=f%28-x%29%20%3D%20%28-x%29%5E2%20-%20%28-x%29%20%3D%20x%5E2%20%2B%20x)
Thus ![f(-x) \neq f(x)](https://tex.z-dn.net/?f=f%28-x%29%20%5Cneq%20f%28x%29)
So this is not a even function
<h3>Option 4</h3>
f(x) = 7
f(-x) = 7
Thus f(-x) = f(x)
Thus it is a even function
Reduce the fraction into decimal numbers
Simply divide the top by the bottom of the fraction. If the division has no remainder, the decimal number is called a terminating decimal.
Now start the division process as below
Therefore,
Is the answer D i might be wrong sorry if i am
Step-by-step explanation:
where is the graph or answer choices at?
Answer:
Those are all right nice job!
Step-by-step explanation: