Question

A circle is centered at N (-6, -2). The point E (-1, 1) is on the circle. Where does point H (-10, -7) lie?

Answer 1

Answer:

  outside circle

Step-by-step explanation:

The difference E -N is ...

  E -N = (-1-(-6), 1-(-2)) = (5, 3)

The difference H -N is ...

  H -N = (-10-(-6), -7-(-2)) = (-4, -5)

The length of line HN will be √(4² +5²), which is a larger number than the length of line EN, which is √(5² +3²).

H lies outside the circle.