Question

Since beth was born, the population of her town has increased at a rate of 850 people per year. On beth 9ths birthday, the total population was nearly 307,650.Write and solve a linear equation on beths 16th birthday.

Answer 1

Answer: There will be 313600 population on beth's 16 birthday.

Step-by-step explanation:

Since we have given that

When Beth was born , the population of her has increased = 850 per year

Let the initial population be x

and let the number of year be n

So, our linear equation becomes,

$x+850n$

On her 9th birthday,

The population becomes 307,650.

So, it becomes,

$x+850\times 9=307650\\\\x+7650=307650\\\\x=307650-7650\\\\x=300000$

So, initial population becomes 300000.

Now, on 16th birthday,

$x+850n\\\\300000+850\times 16=313600$

So, there will be 313600 population on beth's 16 birthday.

Answer 2

Answer:

Equation: x = 850y + 300,000

population on beth's 16th birthday: x= 313, 600

Step-by-step explanation:

If "x" is the population when beth has "y", then

x = 307,650 + 850(y-9)

The population in y years is 307,650 plus the number of years that has pased since she had 9 year: (y-9) multiplied by 850 wich is how much the population increases  in a year.

We can simplify the problem eliminating the parenthesis:

x = 307,650 + 850y - 850*9

x = 850y + 300,000

Thus, for the 16th birthday

y= 16

x = 850(16) + 300,000

x= 313, 600