In each table, x increases by 1. We start with x = 0 and stop with x = 3. So we will focus on the y columns of each table as those are different.
Let's move from left to right along the four tables.
For the first table, we go from y = 1 to y = 2. That's an increase of 1
Sticking with the first table, we go from y = 2 to y = 4. The increase is now 2
Since the increase is not the same, this means the table is not linear. The y increase must be constant. We can rule out choice A
Choice B can be ruled out as well. Why? Because...
the jump from y = 0 to y = 1 is +1
the jump from y = 1 to y = 3 is +2
The same problem comes up as it did with choice A
Choice C has the same problem, but the increase turns into a decrease half the time. We go from y = 0 to y = 1, then we go back to y = 0 so the "increase" is really a decrease. We can think of it as a negative increase. Regardless, this allows us to rule out choice C
Only choice D is the answer. Each time x goes up by 1, y goes up by 2. Therefore the slope is 2/1 = 2
Solution
For this case we can take square root in both sides and we have:
![3x-5=\pm\sqrt[]{19}](https://tex.z-dn.net/?f=3x-5%3D%5Cpm%5Csqrt%5B%5D%7B19%7D)
And solving for x we got:
![x=\frac{5\pm\sqrt[]{19}}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%5Cpm%5Csqrt%5B%5D%7B19%7D%7D%7B3%7D)
then the solutions for this case are:
B and E
Answer:
Choice D is correct answer.
Step-by-step explanation:
We have given two function.
f(x) =2ˣ+5x and g(x) = 3x-5
We have to find the addition of given two function.
(f+g)(x) = ?
The formula to find the addition, we have
(f+g)(x) = f(x) + g(x)
Putting given values in above formula, we have
(f+g)(x) = (2ˣ+5x)+(3x-5)
(f+g)(x) = 2ˣ+5x+3x-5
Adding like terms, we have
(f+g)(x) = 2ˣ+8x-5 which is the answer.
Answer:
x-6 <1
Step-by-step explanation:
