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jok3333 [9.3K]
3 years ago
13

Decrease 5 1/4 m by 50cm answer in metres

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0

To decrease 5 1/4 m (5.25 m) by 50 cm, you first convert 50 cm to m.

To convert cm to m, you divide cm by 100:

\frac{cm}{100}=m


So you can do:

\frac{50cm}{100}=0.5m


Now that you know 50 cm is 0.5 m, you can subtract 5.25 m by 0.5 m:

5.25 m - 0.5 m = 4.75 m  or   4\frac{3}{4} m

polet [3.4K]3 years ago
6 0

5 1/4 m = 5.25m

50 cm = 0.5 m

So 5 1/4 m - 50 cm = 5.25 - 0.5 = 4.75 m

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The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie
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Answer:

The confidence interval is  25.16  < \mu < 26.85

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where is the sample size with values  n =  10

         \= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}

          \= x = 26

The standard deviation is evaluated as

             \sigma  =  \sqrt{\frac{\sum (x-\= x)}{n} }

substituting values

     = \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }

                  \cdot \ \cdot \ \cdot  \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }

     \sigma  =  1.625

The  confidence level is given as 90% hence the level of significance is calculated as

    \alpha  =  100 -90

    \alpha  =10%

   \alpha = 0.10

Now the critical values of \frac{\alpha }{2} is obtained from the normal distribution table as

      Z_{\frac{\alpha }{2} } =  1.645

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  The margin of error is evaluated as

            MOE =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

           MOE =  1.645 *  \frac{1.625 }{\sqrt{10} }

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The  90%, two sided confidence interval is mathematically evaluated as

           \= x  - MOE  < \mu < \= x  + MOE

           26  - 0.845  < \mu < 26  + 0.845

           25.16  < \mu < 26.85

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