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3 years ago

4-inch by 6-inch what is the width of 15 inches for a ratio table

Mathematics

1 answer:

quester [9]3 years ago

3 0

This is a ratio problem; the ratio of the length to width is constant (and therefore equal):

4 /6 = 15 / x

Now, with a ratio, we may do any allowable algebra operation: cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc.

Let's cross-multiply:

4x = (15)(6)

x = 90/4

x = 22.5 in.

You might be interested in

In two or more complete sentences write and solve an equation for the situation and explain how you will solve the equation. Aft

timurjin [86]

Grace weighed 167 pounds before she started her exercise program.

Step-by-step explanation:

Given,

Weight lost by Grace = 45 pounds

Weight of Grace after exercise weeks = 122 pounds

Let,

x represents the weight of Grace before she started the exercise program.

Loss means subtraction, therefore,

We will subtract the lost weight from original weight.

Original weight - Weight lost = Weight after exercise weeks

$x-45=122$

Adding 45 on both sides

$x-45+45=122+45\\x=167\ pounds$

Grace weighed 167 pounds before she started her exercise program.

Keywords: equation, addition

Learn more about addition at:

#LearnwithBrainly

5 0

3 years ago

solve the system of equations below by graphing both equations with a pencil and paper. what is the solution y = x - 1 y = 1/2x

Elan Coil [88]

Answer:

(4,3)

Step-by-step explanation:

$(x-1) = \frac{1}{2}x +1$

$(x-\frac{1}{2}x)-(-1+1)=(\frac{1}{2}x-\frac{1}{2}x)+(1+1)$

$(\frac{1}{2}x/\frac{1}{2})=(2/\frac{1}{2})$

$x=4$

$y=(4)-1$

$y=3$

$y=\frac{1}{2}(4)+1$

$y=2+1$

$y=3$

6 0

3 years ago

The Wall Street Journal reported that automobile crashes cost the United States $162 billion annually (2008 data). The average c

ivanzaharov [21]

Answer:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma= 500$ represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =120 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The confidence2 level is 98% or 0.98 then the significance level would be $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , the critical value for this case would be $z_{\alpha/2}=2.326$ , replacing into formula (b) we got: