Arrange the fractions in order, beginning with the smallest. 9/7,2/9,2/7,2/3

Mathematics

2 answers:

denpristay [2]2 years ago

5 0

Hope this helps!

2/9, 2/7, 2/3, 9/7

katrin2010 [14]2 years ago

3 0

Answer:

2/9, 2/7, 2/3, 9/7

Step-by-step explanation:

9th are smaller than 7th so 2/9 goes first.

7th are smaller than thirds so 2/7 goes second

9/7 is an improper fraction so it is more than one, so 2/3 goes third

Then 9/7

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The sum of three consecutive terms in an arithmetic sequence is 27, and their product is 585. find the three terms.

sammy [17]

$\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\$
$\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4$
$Answer:\ a=5;\ a+d=9; a+2d=13\ vee\ a=13;\ a+d=9;\ a+2d=5$

5 0

3 years ago

Graph this function: y–3= – (x+10) <br> Click to select points on the graph.

Nikolay [14]

Answer:

See below

Step-by-step explanation:

We can simply use a graphing calculator to graph the function

$\boxed{y-3 = -(x+10)}$