The center has coordinates h = -2, k = 5. The radius is sqrt(6). The equation for a circle is as follows:
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
. Filling in using our given info we have
![(x-(-2))^2+(y-5)^2=( \sqrt{6})^2](https://tex.z-dn.net/?f=%28x-%28-2%29%29%5E2%2B%28y-5%29%5E2%3D%28%20%5Csqrt%7B6%7D%29%5E2%20)
. Simplifying that down we have an equation of
![(x+2)^2+(y-5)^2=6](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%2B%28y-5%29%5E2%3D6)
. There you go!
(part A) 800 (part B) but in this case in depends if your subtracting or dividing but if so of subtraction then 92 andbif dividing its 12.5
Let the number of buses be x
and car be y
• Total vehicle gone are 21
x + y = 21 ..... ( i ) × 4
• There are 30 people in buses and 4 on car total people gone are 318
30x + 4y = 318 ..... ( ii )
Sub ( ii ) from ( i ) × 4
4x + 4y - ( 30x + 4y ) = 84 - 318
4x + 4y - 30x - 4y = - 234
- 26y = - 234
y = 9
Putting the value of y in eq i
x + y = 21
x = 21 - 9
x = 12
Total buses are 12
and total car are 9
Hope it helps...