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Grace [21]
3 years ago
8

Find the missing numerators in each of the following fractions: a. 5⁄6 = ?⁄12 b. 2⁄4 = ?⁄36 c. 2⁄5 = ?⁄20 d. 4⁄25 = ?⁄100

Mathematics
2 answers:
ioda3 years ago
7 0
A. 10
Multiply numerator and denominator by 2. So 6(2)=12 and 5(2)=10
B. 18
Multiply numerator and denominator by 9. So 4(9)=36 and 2(9)=18
C. 8
Multiply numerator and denominator by 4. So 5(4)=20 and 2(4)=8
D. 16
Multiply numerator and denominator by 4. So 25(4)=100 and 4(4)=16
pshichka [43]3 years ago
7 0

Answer:

To find: Missing Numerators.

let the missing variable in each part be x.

A).

\frac{5}{6}=\frac{x}{12}

\frac{5}{6}\times12=x

x=10

Thus, Missing Numerator in this part is 10.

B).

\frac{2}{4}=\frac{x}{36}

\frac{2}{4}\times36=x

x=18

Thus, Missing Numerator in this part is 18.

C).

\frac{2}{5}=\frac{x}{20}

\frac{2}{5}\times20=x

x=8

Thus, Missing Numerator in this part is 8.

D).

\frac{4}{25}=\frac{x}{100}

\frac{4}{25}\times100=x

x=16

Thus, Missing Numerator in this part is 16.

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8 0
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