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goblinko [34]
3 years ago
6

A relation is plotted as a linear function on the coordinate plane starting at point C (0,−1)(0,−1) and ending at point D (2,−11

)(2,−11) .
What is the rate of change for the linear function and what is its initial value?

the rate of change is ______ and the intivial value is______
Mathematics
1 answer:
Alika [10]3 years ago
4 0
To find the rate of change, or slope, pick two points. The slope, is change in y coordinates over change in x coordinates.
slope =  \frac{y2-y1}{x2-x1}.

In this case, the slope is 
\frac{-11+1}{2-0} =  \frac{-10}{2} = -5.
Remember that subtracting a negative number equals adding the number without the negative sign.
a-(-b) = a+b

Now for the y-intercept. The y-intercept is where the graph intersects the y-axis, where x = 0.
You have the coordinate (0, -1), where x = 0. So the y-intercept is -1.

Putting these values into the slope-intercept form y = mx+b, the equation is
y = -5x - 1
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Elina [12.6K]

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8 0
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C

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'x=' create vertical lines which are not functions whereas

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