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Vlad [161]
3 years ago
14

Not really sure how to do this

Mathematics
1 answer:
wariber [46]3 years ago
6 0

Answer:

Step-by-step explanation:

\begin{bmatrix}6x=3y-7\\ 9y-18x-9=0\end{bmatrix}\\\mathrm{Isolate}\:x\:\mathrm{for}\:6x=3y-7:\quad x=\frac{3y-7}{6}\\6x=3y-7\\\mathrm{Divide\:both\:sides\:by\:}6\\\frac{6x}{6}=\frac{3y}{6}-\frac{7}{6}\\Simplify\\x=\frac{3y-7}{6}\\\mathrm{Subsititute\:}x=\frac{3y-7}{6}\\\begin{bmatrix}9y-18\cdot \frac{3y-7}{6}-9=0\end{bmatrix}\\\mathrm{Refine\:}9y-18\frac{3y-7}{6}-9=0\\12=0\\12=0\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}\\No\:Solution

I hope this is what you wanted

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Q1.

a. three hundred sixty-four thousand eight hundred twenty-five

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7       x
--- = ---
12     5

Solve this for x.  One way to do this would be to cross-multiply, obtaining 12x = 35, and solving this result for x.  x will be a fraction.  Write the numerator and denominator in the boxes given.
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