Question

Not really sure how to do this

Answer 1

Answer:

Step-by-step explanation:

$\begin{bmatrix}6x=3y-7\\ 9y-18x-9=0\end{bmatrix}\\\mathrm{Isolate}\:x\:\mathrm{for}\:6x=3y-7:\quad x=\frac{3y-7}{6}\\6x=3y-7\\\mathrm{Divide\:both\:sides\:by\:}6\\\frac{6x}{6}=\frac{3y}{6}-\frac{7}{6}\\Simplify\\x=\frac{3y-7}{6}\\\mathrm{Subsititute\:}x=\frac{3y-7}{6}\\\begin{bmatrix}9y-18\cdot \frac{3y-7}{6}-9=0\end{bmatrix}\\\mathrm{Refine\:}9y-18\frac{3y-7}{6}-9=0\\12=0\\12=0\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}\\No\:Solution$

I hope this is what you wanted