<h3>
Answer: sometimes true</h3>
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Explanation:
The plane P can be thought of a perfectly flat ground. Now imagine a flag pole which represents line GH. If AB is drawn in chalk on the pavement, and this line AB intersects the base of the flagpole, then we've made AB and GH intersect. However, this example shows that GH is <u>not</u> on the plane P.
Is it possible to have GH be in the the plane? Yes. We could easily draw another chalk line on the ground to have it intersect AB somewhere. But as the previous paragraph says, it's also possible that GH is not in the plane.
Therefore, the statement is sometimes true
Log₅(25/125)
=log₅(1/5)
=log₅(1)-log₅(5)
=0-1
=-1
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USE:
log₅(x)-log₅(p)=log₅(x/p)
Remember that:
5⁰=1,
5¹=5
velocity is the slope (which can be calculated after finding the derivative) → given function f(x), velocity = f'(x).
acceleration is the slope of the velocity (which can be calculated after finding the derivative of the velocity) → given function f(x), acceleration is f''(x)
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1a) A → B
f(x) =
f'(x) =
1b) B → C
f(x) =
f'(x) = = -5
1c) C → D
f(x) = 20
f'(x) = 0
Hope this helps!
Answer:
A. 63 minutes
Step-by-step explanation:
Because you adding all the time together, and if they mean by "start" including greeting the chidren, then it would be 53 minutes. But I'm pretty sure its A.
Answer:
x+y=13 and 25x+10y=265;
x= number of quarters and y= number of dimes.
Step-by-step explanation:
marked as right