<span>y-2>1/2(x-2) can be expanded as follows: y - 2 > (1/2)x - 1
Mult. all terms by 2 to remove the fractions:
2y - 4 > x - 2
Add 4 to both sides: 2y > x + 2
Div. both sides by 2: y > (1/2)x + 1 (answer)</span>
Answer:
Below in bold.
Step-by-step explanation:
1) ( a^2 + b^2 = (a + b)^2 - 2ab
= 29 - 2(6)
= 29-12
= 17.
2). (x - y)^2 = x^2 + y^2 - 2xy
so 20 = 18 - 2xy
2xy = 18-20 = -2
xy = -1.
3). 1/x + x = 7
(1/ x + x)^2 = 1/x^2 + x^2 +x/x + x/x
= 1/x^2 + x^2 + 2
But(1/x + x)^2 = 7^2 = 49
so 1/x^2 + x^2 + 2 = 49
so 1/x^2 + x^2 = 49 - 2 = 47.
Answer:
Option B
The answer is 16
Step-by-step explanation:
<h3><u>Given</u>;</h3>
<h3><u>To </u><u>Find</u>;</h3>
Now,
4(v – 13) = 12
4(v – 13)/4 = 12/4
v – 13 = 3
v – 13 + 13 = 3 + 13
v = 16
Thus, The value of v is 16
<u>-TheUnknownScientist 72</u>
The form is y=mx+b
3x=-2y+4 (add 2y)
3x+2y=4 (subtract 3x)
2y=-3x+4 (divide by 2)
y= -2/3x+2
<u>Answer</u> i think the first one goes down by .3 every time but i am not 100$
Step-by-step explanation:
