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4 years ago

30 POINTS!!!!! URGENT!

Mathematics

2 answers:

zzz [600]4 years ago

7 0

Answer:

Average daily balance: Add all balances up and divide by the number of days.

157.63*9+239.98*1+239.98*4+180.38*1+180.38*9+190.57*1+190.57*6 gives us our total of 5756.36, and there were 9+1+4+1+9+1+6=31 days, so 5756.36/31 gives us our average of 185.69, or the fourth option

Daily interest rate: 24.99/365, as a percent, which is the first option

Finance charge: This is the cost of borrowing, and does not seem to be given, so we can take it to be the lowest amount, or the third value

New account balance: Again, this does not seem to be given, but the only option remaining is the second one

Step-by-step explanation:

vekshin14 years ago

3 0

Step-by-step explanation:

Average daily balance: Add all balances up and divide by the number of days.

157.63*9+239.98*1+239.98*4+180.38*1+180.38*9+190.57*1+190.57*6 gives us our total of 5756.36, and there were 9+1+4+1+9+1+6=31 days, so 5756.36/31 gives us our average of 185.69, or the fourth option

Daily interest rate: 24.99/365, as a percent, which is the first option

Finance charge: This is the cost of borrowing, and does not seem to be given, so we can take it to be the lowest amount, or the third value

New account balance: Again, this does not seem to be given, but the only option remaining is the second one

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3 years ago

If you start with 85 milligrams of Chromium 51, used to track red blood cells, which

zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes ( $m$ ), measured in milligrams, decreases exponentially in time ( $t$ ), measured in days. The model that represents such decrease is described below:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ (1)

Where:

$m_{o}$ - Initial mass, in milligrams.
$m(t)$ - Current mass, in milligrams.
$\tau$ - Time constant, in days.

In addition, the time constant is defined in terms of half-life ( $t_{1/2}$ ), in days:

$\tau = \frac{t_{1/2}}{\ln 2}$ (2)

If we know that $m_{o} = 85\,mg$ , $t_{1/2} = 27.7\,d$ and $m(t) = 8.5\,mg$ , then the time required for decaying is:

$\tau = \frac{t_{1/2}}{\ln 2}$

$\tau = \frac{27.7\,d}{\ln 2}$

$\tau \approx 39.963\,d$

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$t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}$

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About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

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4 years ago

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Minchanka [31]

Answer:

C. C. C.

Step-by-step explanation:

Based on my research

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