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Semenov [28]
3 years ago
10

Plz help me with these problems

Mathematics
2 answers:
Sophie [7]3 years ago
4 0

Answer:

The answer for 16 is A,  the answer for 20 is D, and the answer for 25 is A

Step-by-step explanation:

For 16, the equation is 6a = 72. 6a is also equal to 6*a. To get a one side by itself, you have to divide both sides by 6.

For 20, it only makes sense for it to be a triangular prism because it has 2 triangles as the base and 3 faces

For 25, you can subtract what was the leftovers from the total number of pizzas. 8 - 1 3/4 - 5/6 is about 5.41, which is closer to 5 so the answer is 5.

elena-14-01-66 [18.8K]3 years ago
3 0

Answer: number 16 is d

number 20 is d

Step-by-step explanation:

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6 2/8 + 4 3/4 whats the answer
gavmur [86]

Answer:

11

Step-by-step explanation:

6 2/8 = 6 1/4

6 1/4 + 4 3/4 = 10 4/4

11

4 0
3 years ago
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In the triangle, ABC, the measure of ∠A is 30° and the measure of ∠C is 90°. What is the measure of ∠B?
Molodets [167]

Answer:

60°

Step-by-step explanation:

angle A +angle B +angle C = 180

30° +B+90°= 180

120°+B=180°

B=180°-120°

B=60°

8 0
3 years ago
Solve by factoring: x2 – 9x + 20 = 0
gayaneshka [121]

Answer:

Answer

Given equation is:

x

2

−9x+20=0

⇒x

2

−5x−4x+20=0

⇒(x−4)(x−5)=0

⇒x=4andx=5

3 0
3 years ago
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Kazeer [188]
Step by step by its the thirds pne
6 0
3 years ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit  10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is \overline A=\textrm{Missing a target at least once}

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, P(A)=0.95^{10}=0.5987

We know that the sum of probability of an event and its complement is 1.

So, P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

6 0
3 years ago
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