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bogdanovich [222]
3 years ago
14

Find the surface area of the cone with a diameter of 12 centimeters and a slant height of

Mathematics
1 answer:
Andrej [43]3 years ago
8 0

Answer:

lateral surface area is 160.14 square cm.

Total surface area is 273.16  square cm  

Step-by-step explanation:

Lateral surface area of cone is given by \pi rl

where r is radius of cone

and l is slant height of cone.

l = 85 millimetres

we know that 10 millimetres is equal to 1 cm

Thus 85 millimetres is equal to 8.5 cm

Thus slant height(l) in cm is 8.5\pi rl\\=>\pi 6*8.5\\=> 3.14*51\\=>160.14

we will use value of \pi as 3.14

Diameter of cone = 12 cm

we know that radius is equal to half of Diameter

radius of given cone = 1/2 *Diameter = 1/2 * 12 = 6 cm.

Thus lateral surface area of cone is given by

\pi rl\\=>3.14*6*8.5\\=>153

Thus, lateral surface area is 160.14 square cm.

Area of base of cone will be area of circular base

area of circle is given by \pi r^2

Thus area of base is given below

\pi r^2\\=>3.14*6^2\\=>113.04

area of base is 113.04 square cm

Total surface area of cone is sum of area of base and lateral surface area

Total surface area = 160.14+113.04 = 273.16  square cm.

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The two triangles are similar What is the value of x? Enter your answer in the box x =
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3 years ago
Determine which set of numbers can be the lengths of the sides of a triangle.
prisoha [69]

Answer:

A) 13, 10, 16

Step-by-step explanation:

The Triangle Inequality Theorem will help you solve this question. The Triangle Inequality Theorem states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side.

The options that are given are:

  • A) 13, 10, 16
  • B) 1, 2, 3
  • C) 5.2, 11, 4.9
  • D) 208, 9, 219

Lets solve each one to figure out if they could be the lengths of a triangle.

A) 13, 10, 16.

We can write three inequalities to see if the lengths are true.

13 + 10 > 16

10 + 16 > 13

13+ 16 > 10

Solve each one.

23 > 16

26 > 13

29 > 10

According to the information above, the set of numbers from option A does  fit the Triangle Inequality Theorem. Therefore, they are possible lengths.

B) 1, 2, 3

Write three inequalities:

1 + 2 > 3

2 + 3 > 1

3+ 1 > 2

Solve each.

3 > 3

5 > 1

4 > 2

As you see, only two lengths fit the theorem, but the third side (3 > 3) does not. This set of lengths is not a possible set for a triangle.

C) 5.2, 11, 4.9

Write three inequalities:

5.2 + 11  > 4.9

4.9 + 11 > 5.2

5.2 + 4.9 > 11

Solve each.

16.2 > 4.9

15.9 > 5.2

10.1 > 11

As you see, only two sides lengths can repsent the lengths of a triangle but the third does not, so its not a possible set of lengths for a triangle.

D) 208, 9, 219

Write three inequalities:

208 + 9 > 219

219 + 9 > 208

208+ 219 > 9

Solve each.

217 > 219

228 > 208

427 > 9

Although two lengths fit the theorem, one length does not, so this a not a possible set of lengths.

In summary, only one set of lengths is possible for a triangle, with is A.

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3 years ago
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Savatey [412]

Given:

Points on the line are (5, 7) and (5, -5).

To find:

Equation of a line parallel to line l.

Solution:

Let us first find the slope of line l.

Slope of the line formula:

$m=\frac{y_2-y_1}{x_2-x_1}

$m=\frac{-5-7}{5-5}

$m=\frac{-12}{0}

m = undefined

The line intersects at x-axis, so the y-intercept is 0.

Equation of line l is x = 5.

<em>If two lines are parallel, then their slopes are equal.</em>

In the option, find the line which also have slope undefined.

Option A: x = 5y

Divide by 5 on both sides, we get

$\frac{x}{5} =y

Here slope is \frac{1}{5}. So it is not parallel to line l.

Option B: x = -2

Here, the slope is undefined. It also passes through the x-axis.

Therefore, it is parallel to line l.

Option C: y = 5

Here, the line passes through y-axis.

So, it is not parallel to line l.

Option D: y = -5x.

Here, the slope is -5.

So, it is not parallel to line l.

Hence x = -2 is and equation for a line that is parallel to line l in the graph.

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