Answer:
The domain for x is all real numbers greater than zero and less than 5 com
Step-by-step explanation:
<em><u>The question is</u></em>
What is the volume of the open top box as a function of the side length x in cm of the square cutouts?
see the attached figure to better understand the problem
Let
x -----> the side length in cm of the square cutouts
we know that
The volume of the open top box is
we have
substitute
Find the domain for x
we know that
so
The domain is the interval (0,5)
The domain is all real numbers greater than zero and less than 5 cm
therefore
The volume of the open top box as a function of the side length x in cm of the square cutouts is
-30-6r=36
We move all terms to the left:
-30-6r-(36)=0
We add all the numbers together, and all the variables
-6r-66=0
We move all terms containing r to the left, all other terms to the right
-6r=66
r=66/-6
r=-11
The answer is '<span>f(x) is an odd degree polynomial with a positive leading coefficient'.
An odd degree polynomial with a positive leading coefficient will have the graph go towards negative infinity as x goes towards negative infinity, and go towards infinity as x goes towards infinity.
An even degree polynomial with a negative leading coefficient will have the graph go towards infinity as x goes toward negative infinity, and go towards negative infinity as x goes toward infinity.
g(x) would have a a positive leading coefficient with an even degree, as the graph goes towards infinity as x goes towards either negative or positive infinity.
</span>
(f + g)(x) = f (x) + g(x)
= [3x + 2] + [4 – 5x]
= 3x + 2 + 4 – 5x
= 3x – 5x + 2 + 4
= –2x + 6
Answer:
this is how u solve this
Step-by-step explanation:
