F(x) = 3x+1
G(x) = X^2 - 6
F(G(x)) = F(X^2 - 6) = 3(X^2 - 6) + 1 = 3X^2 - 18 + 1 = 3X^2 -17
F(G(x)) = 3X^2 - 17
You could write this by going 63+42 or add 63 and 42
hope that's what you are looking for ;-)<span />

We have to find out the value of the fraction.
<u>Let us assume that:</u>

<u>We can also write it as:</u>




<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

<u>By quadratic formula:</u>







<u>But </u><u>"</u><u>x"</u><u> cannot be negative. Therefore:</u>

So, the value of the fraction is 1 + √2.
Answer:
3,915 mi
Step-by-step explanation:
Answer:
81
Step-by-step explanation:
9 x 9 = 81
So, 81 is the perfect square.