Answer:
(a) (C) No. The probability of drawing a specific second card depends on the identity of the first card.
(b)
(c)
(d)
Step-by-step explanation:
(a)The outcomes on the two cards are not independent because since the cards are drawn without replacement, the probability of drawing a specific second card depends on the identity of the first card.
(b)P(ace on 1st card and jack on 2nd).
Number of Ace = 4
Number of Jack = 4
P(ace on 1st card and jack on 2nd)

(c) P(jack on 1st card and ace on 2nd).
Number of Ace = 4
Number of Jack = 4

(d) Probability of drawing an ace and a jack in either order.
=P(Ace and Jack) Or P(Jack and Ace)
=P(Ace and Jack) + P(Jack and Ace)

The oil tanker is 96.86 meters longer than the cruise ship. and both of them put together is 820.6 meters long
Starting with <span>3x^2-7x+12=0, we divide all four terms by 3, resulting in the following factored form:
</span><span>
3(</span><span>x^2-[7/3]x+4)=0.
</span><span>
Since 3 cannot equal 0, we can focus on the following:
x^2 - 7/4 x =-4
This completes the assignment (describe Joe's steps up to this point).
If you wish to go further:
Next, take HALF of the coefficient of x and square your result:
(-7/[4][2])^2 = 49/64
Add this to both sides of </span>x^2 - 7/4 x =-4: <span>x^2 - 7/4x + 49/64 =-4+49/64
Rewrite the left side as (x-7/8)^2 and the right side as 49/64 - 256/64
Simplify the right side by combining these terms: -207/64
Then x-7/8 = plus or minus (1/8)sqrt(-207)
Next, x = 7/8 plus or minus (1/8)*i*</span>√207, or
7 plus or minus i*√207
x = ----------------------------------
8
I take it you meant θ angle, anyway.
we know the tan(θ) = -4/7... alrite, we also know that 270° < θ < 360°, which is another to say that θ is in the IV quadrant, where the adjacent side or "x" value is positive whilst the opposite side or "y" value is negative.
we have

using a graph tool
see the attached figure
For t=0 d=4 -------> the y-intercept
that means that at the time t=0 the house was four units away.
For t=60 min d=0 -------> x-intercept
that means he was already at home at the time t=60 minutes.
therefore
the graph of this equation represents the walk towards the house