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yulyashka [42]
3 years ago
11

What is the slope of a line perpendicular to a line that's passes through (3,8) and (1,-4)?

Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

-1/6

Step-by-step explanation:

First find the slope of the line through the points

m = (y2-y1)/(x2-x1)

    = (-4-8)/(1-3)

     = -12/-2

      =6

Now we need to find the slope of the line that is perpendicular

Perpendicular lines multiply to -1

6 * mp = -1

mp = -1/6

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The radius of a sphere is increasing at a rate of 2 mm/s. How fast is the volume increasing when the diameter is 80 mm? Evaluate
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Well, if it is increasing at a fixed rate of 2 mm/s, then the volume would still be increasing at a rate of 2 mm/s when the diameter is 80 mm, if I understand your question correctly.
7 0
4 years ago
$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent
photoshop1234 [79]

\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
\\
\text{we know that the amount after t year when compounded is given by}\\
\\
A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
\\
\text{here P is the principal amoount, so }P=7000,\\
\\
\text{r is the interest rate, }r=11\%=0.11\\
\\
\text{n is the number of times in a year, here semiannulay, so }n=2,\\
\\
\text{and t is the time, so }t=21\\
\\
\text{so the amount after 21 years is}

A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
\\
\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
\\
\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
\\
\Rightarrow A\approx 66328.68

So the amount after 21 years is: $66328.68

7 0
3 years ago
Using the numbers -4,10, 8, 2, -3, -5 , create two expreasioms that equal 6
timama [110]
I would say take 2 from eight which equals 6
5 0
3 years ago
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Answer:

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Step-by-step explanation:

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8 0
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Eddi Din [679]

Answer:

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2 years ago
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