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3 years ago

Find the median of the data in the box plot below.

Mathematics

1 answer:

Law Incorporation [45]3 years ago

5 0

Answer:

Median = 7 kg

Step-by-step explanation:

Hello!

To construct a box plot you have to follow the steps:

1) identify the 1st quartile (it represents the lower limit of the box)

2) identify the 3rd quartile (it represents the upper limit of the box)

3) Identify the 2nd quartile or median, as you know it separates the bottom 50% of the data distribution from the top 50%. You'll always find it represented by a line within the two limits of the box.

4) Identify the minimum value. The left or lower whisker is extended from the 1st quartile to the minimum value.

5) Identify the maximum value. The right or upper whisker is extended from the 3rd quartile to the maximum value.

In this example, the lower limit of the box is 6 and the upper limit is 8.5, within the box you find the median is represented by a vertical line at 7

Q1= 6 kg

Q2/ Median= 7 kg

Q3= 8.5 kg

(Sketch in attachment)

I hope this helps!

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Suppose it is known that the distribution of purchase amounts by customers entering a popular retail store is approximately norm

Ket [755]

Answer:

69.15% probability that a randomly selected customer spends less than $105 at this store

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 100, \sigma = 10$

What is the probability that a randomly selected customer spends less than $105 at this store?

This is the pvalue of Z when X = 105. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{105 - 100}{10}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

69.15% probability that a randomly selected customer spends less than $105 at this store

7 0

3 years ago

Read 2 more answers

A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi

rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

$P(9$

Recall Chebyshev's inequality that

$P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\$

Comparing with the Ii equation which is appropriate here we find that

$\mu =14.5$

Next what we find is

$k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071$

Thus from the given information we find that

$\mu = 14.5\\\sigma = 5.071\\k = 1.084$

5 0

4 years ago

Lee has 3 children, the oldest is twice as old as the oungest, the middle is 5 years older than the youngest, the sum of the chi

tangare [24]

Oldest = 2x
Middle = x + 5
Youngest = x

2x + x + 5 + x = 57
combine like terms

4x + 5 = 57
subtract 5 from both sides

4x = 52
divide both sides by 4 to isolate x

x = 13

Oldest = 2x = 2(13) = 26
Middle = x + 5 = 13 + 5 = 18
Youngest = x = 13

8 0

3 years ago

Read 2 more answers

Write the equation of the line shown in point-slope form. (2,1) (3,8)

Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.