There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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Answer:
ask your teacher it would be good for you and also teachers give u good thing about that okay but i can't help you sorry.
Step-by-step explanation:
Greatest common factor between each term is 20, so you'd divide both by 20 to reduce this to 20(p - 3).
Answer:
For example, suppose we weigh five children. ... 5. ∑ i=1 xi. = x1 + x2 + x3 + x4 + x5. = 10 + 12 + 14 + 8 + 11. = 55. ... We also use sigma notation in the following way: 4 ... j2 = 12 + 22 + 32 + 42 = 30.
Missing: 17 | Must include: 17Summary measures for this data set are ... 17 18. 19 20. Observedresult. 0. 1. 0. 1. 1. 0. 1. 0. 1. 1. Total so far. 4. 5. 5. 6 ... 5. 10. 15. 20. 25. 30. 35. 40 . Toss. Figure S2.1 Proportion P, 40 tosses of a coin.
For volume you would do 20 x 8.5 x 7.5 = 1275 ft^3
For surface are you would add up all the area of the faces
left and right face = 8.5 x 7.5 = 63.75 each
front and back = 20 x 8.5 = 170 each
top and bottom = 20 x 7.5 = 150 each
total = 767.5 ft^2