Can you please help me?

Mathematics

1 answer:

zubka84 [21]3 years ago

3 0

So the right answer is 9

Look at the attached picture

Hope it will help you...

Good luck on your assignment

You might be interested in

Find the remainder when 1! + 2! + 3! + ..... + 100! is divided by 24 .

ikadub [295]

Answer:

the answer is 9

..............

6 0

2 years ago

Evaluate 6 + 4/a + b/3 when a = 4 and b = 3.

GREYUIT [131]

The answer to your problem would be 8.

8 0

3 years ago

Solve this quadratic equation. Show all work. 4x^2-2x-5=0

kicyunya [14]

X= -b⁺₋ √b²-4ac/2a
x= (-(-2)⁺₋√(-2)²- 4(4)(-5))/2(4)
x= 4 ⁺₋√4+80/8
x= (4⁺₋ 9.165)/8
x= 4+9.165)/8 or x= 4-9.165)/8
x= 1.40 or x= -0.896

6 0

3 years ago

Use the method of completing the square to write the equation of the given parabola in this form:

siniylev [52]

Formula is y = a(x-h)^2 + k

Where h is 1 and k is 1

f (x) = a(x-1)^2 + 1

-3 = a(0-1)^2 + 1

-3 = a(-1)^2 + 1

-3 = a(1) + 1

-3 - 1 = a

-4 = a

a = -4

A must be equal to -4

y = -4(x-1)^2 + 1

0 = -4(x-1)^2 + 1

4(x^2 - 2x + 1) - 1 = 0

4x^2 - 8x + 4 - 1 = 0

4x^2 - 8x + 3 = 0

4x^2 - 8x = -3

Divide fpr 4 each term of the equation....x^2 - 2x = -3/4

We must factor the perfect square ax^2 + bx + c which we don't have. We must follow the rule (b/2)^2 where b is -2....(-2/2)^2 = (-1)^2 = 1 and we add up that to both sides

x^2 - 2x + 1 = -3/4 + 1

x^2 - 2x + 1 = 1/4

(x-1)^2 = 1/4

square root both sides x-1 = (+/-) 1/2

x1 = +1/2 + 1 = 3/2

x2 = -1/2 + 1 = 1/2

x-intercepts are 1/2 and 3/2, in form (3/2,0); (1/2,0)

6 0

3 years ago

Read 2 more answers

16) (lly-32) (6x + 7) What’s X

Y_Kistochka [10]

This has alot of information missing. Can you please repost this with more detailed information? Thanks.

6 0

3 years ago