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Ronch [10]
3 years ago
9

The coordinates of three vertices of a square are (4, 14), (10, 14), and (4,8).

Mathematics
2 answers:
solong [7]3 years ago
8 0

Answer:c

Step-by-step explanation:

Hope u do good

nydimaria [60]3 years ago
4 0
Answer:

I think it’s C

I hope this helps you!!!!!
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Solve the system by the method of your choice x=3y-6,2x-6y=-12
igor_vitrenko [27]

The "system" of equations can't be solved for (x, y), because there's no "system" of equations given.  There's really only one equation.

Either of these two equations can be massaged to look exactly like the other one.  And if you graph both equations, you find that they're both the same line on the graph.

ANY point on the line is a solution to both equations ... and we all know how many different points there are on a line.

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3 years ago
Select the fraction that is NOT in lowest terms . which of these fractions is not in lowest term?
Kisachek [45]

Answer:

14/21

Step-by-step explanation:

14/21 is divisible by 7, and can reduce to 2/3

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3 years ago
After traveling 345 miles, the
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Find the area of the rectangle:
kumpel [21]
10 ft and 2 because I did the math
6 0
2 years ago
Read 2 more answers
Select ALL the correct answers.
Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0
2 years ago
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