The answer to the question above is the last one. Because when x+5 is expanded.
It will be
x^2 + 10x + 25 = 1
Then, if you transpose the 1
It will be a negative which will result to
x^2 + 10x + 25 -1 = 0
and it leads to the x^2 + 10x +24 = 0
I think the answer maybe 9t+5x
Answer:
B,D
Step-by-step explanation:
The small number is always the bigger one in negatives because it is closer to 0 in a timeline
_-6_-5_-4_-3_-2_-1_0_1_2_3_4_5_6
<u>Answer:
</u>
Slope of a line perpendicular to the line y=8x+1 is
<u>Solution:
</u>
Given y=8x+1
The slope - intercept form equation of line is given as
y = mx + c --- eqn 1
Where m is the slope of the line.
The coefficient of “x” is the value of slope of the line.
"c" is the y – intercept which is the value of y at the point where the line crosses the y-axis
From question, given that y = 8x + 1
Comparing the given equation y=8x+1 with equation 1, we get
m = 8 and c = 1
The equation of a perpendicular line to y=8x+1 must have a slope that is the negative reciprocal of the original slope.
![\mathrm{m}_{\text {reciprocal }}=-\frac{1}{8}](https://tex.z-dn.net/?f=%5Cmathrm%7Bm%7D_%7B%5Ctext%20%7Breciprocal%20%7D%7D%3D-%5Cfrac%7B1%7D%7B8%7D)
Hence the slope of the line perpendicular to the line y=8x+1 is