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Makovka662 [10]
3 years ago
12

Please answer this correctly

Mathematics
2 answers:
crimeas [40]3 years ago
4 0

Answer:

27 yards squared.

Step-by-step explanation:

Perimeter of the left rectangle: 24

Perimeter of the right rectangle: 24

3x2=6

24-6=18

18/2=9

So the vertical length (width) of the orange rectangle is 9 yards.

Thus, the a rea is 9x3,  which is 27 yards squared

dexar [7]3 years ago
4 0

Answer:

27

Step-by-step explanation:

8+4+8+4=24

3+3=6

24-6=18

18/2=9

9*3= 27

plz mark me brainliest!

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Multiply the number outside of the parenthesis with the numbers inside the parenthesis
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4 years ago
Evaluate expression- Which of these answer choices are correct answer to the question
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Answer:

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3 years ago
Complete two ratios to describe the model. 4 dark blue triangles and 12 light blue triangles. The ratio of light blue triangles
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1:3

Step-by-step explanation:

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3 years ago
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On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
4 years ago
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