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maw [93]
3 years ago
13

The speed of sound is approximately 1.2 × 103 km/h. How long does it take for sound to travel 7.2 × 102 km? Write the answer in

minutes.
(Please show your work)
Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0
Time = distance
           ---------------
             speed
           
         =    7.2 x 10^2 
             --------------------
               1.2 x 10^3 
          
         =     0.6 hrs = 0.6 x 60 = 36 minutes.

Hope this helps!



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Jack usually mows his lawn in 6 hours. marilyn can mow the same yard in 4 hours. How much time would it take for them to mow the
Anuta_ua [19.1K]

Answer:

2.4 hours or 2 hours and 24 minutes

Step-by-step explanation:

Jack mows 1/6 of the lawn per hour while Marilyn mows 1/4 of the lawn together. Adding up those rates yields in their combined mowing rate:

R = \frac{1}{6}+ \frac{1}{4}\\R=\frac{10}{24}

The time required for them to mow the entire lawn is:

t = \frac{1}{R}\\t = \frac{1*24}{10}\\ t=2.4\ hours

It would take them both 2.4 hours to mow the lawn together.

5 0
3 years ago
Tewanda read a 2000 word news article in 8 minutes. how fast did she read the article
nydimaria [60]
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A ball is thrown from an initial height of 6 feet with an initial upward velocity of 18 fts. The ball's height h (in feet) after
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7 0
3 years ago
A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.
AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0
3 years ago
Use quadratics---------------
Elza [17]
A square's area is the square of the sides 

square area= side²
side=\sqrt{96x^5} 

side=\sqrt{2(2)(2)(2)(3)x^2(x)}
side=4x^2 \sqrt{3x}

OR we can divide it 
    |_ 96x^5
 x²|_ 96x^3
 x⁴|_ 96x
4x⁴|_ 3x

5 0
4 years ago
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