Answer:
Step-by-step explanation:
Find the median of the first and third quartiles
81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 92
50, 55, 59, 69, 79, 81, 90, <u> 92,</u> 92, 95, 97, 116, 122, 125, 183.
The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69
The third quartile: <u>92, 95, 97, 116, 122, 125, 183</u>: median of the third quartile is 116.
The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.
There are no outliers in this set of data
