I don't know if I'm right but I think its -243
Answer:
x^5 o aca mas profesional 
jaja
Step-by-step explanation:
supongo que lo que tienes que hacer es agrupar las dos x. Si es asi, asi seria.
Let x is the price for one ticket in section A and y for section B.
In first week they paid <span>$108 for 6 tickets in section A and 10 tickets in section B.
So,
6x + 10y = 108
And in t</span><span>he following week, they paid $104 for 4 tickets in section A and 12 tickets in section B.
So,
4x + 12y = 104
12y = 104 -4x
y= (104 -4x) /12
now, put this value for y in first equation
6x +10(104 - 4x / 12) = 108
multiplying all terms with 12
72x +10(104 -4x) = 1296
72x + 1040 -40x = 1296
32x = 256
x = 8
So, price for one ticket in section A is $8.
</span>
Hello,
Answer C
......|x^3|x^2|...x|1
......|..-3|..-2|..-1..|-2
x=2|.....|..-6|..-16|.-34
......| -3.|-8..|..-17|-36
