An invisible path determining the way of travel from one place to another.

Compared to using a command line, an advantage to using an operating system that employs a gui is ________.

artcher [175]

Compared to using a command line, an benefit to using an operating system that employs a GUI exists you do not have to memorize complicated commands.

<h3>What is operating system?</h3>

An operating system (OS) exists as the program that, after being initially loaded into the computer by a boot program, contains all of the other application programs on a computer. The application programs create use of the operating system by completing requests for services through a specified application program interface (API).

A GUI utilizes windows, icons, and menus to carry out commands, such as opening, deleting, and moving files. Although a GUI operating system is especially navigated using a mouse, a keyboard can also be utilized via keyboard shortcuts or arrow keys.

The GUI, a graphical user interface, exists as a form of user interface that permits users to interact with electronic devices via graphical icons and audio indicators such as primary notation, instead of text-based UIs, typed command labels, or text navigation.

Hence, Compared to using a command line, an benefit to using an operating system that employs a GUI exists you do not have to memorize complicated commands.

To learn more about operating system refer to:

brainly.com/question/22811693

#SPJ4

7 0

2 years ago

When evaluating the validity of a website beyond its URL, you can practice the "rule of 3" which means

Schach [20]

Any information on a website should be findable within 3 mouse clicks.

5 0

3 years ago

Read 2 more answers

How does a cat get out of a bush?

Alex17521 [72]

Answer:

that lil mf crawls through the bush

Explanation:

hes fast ngl

7 0

2 years ago

Write a program that prompts the user to input a number. The program should then output the number and a message saying whether

Gala2k [10]

Answer:

Following is the program in C++ Language

#include <iostream> // header file

using namespace std; // namespace std

int main() // main method

{

int n; // variable declaration

cout<<" Please enter the number :";

cin>>n; // Read the number

if(n>0) // check the condition when number is positive

{

cout<<n<<endl<<"The number is Positive"; // Display number

}

else if(n<0) // check the condition when number is Negative

{

cout<<n<<endl<<"The number is Negative";// Display number

}

else // check the condition when number is Zero

{

cout<<n<<endl<<"The number is Zero";// Display number

}

return 0;

}

Output:

Please enter the number:

64

The number is Positive

Explanation:

Following are the description of the program

Declared a variable "n" of int type.
Read the value of "n" by user.
Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
Finally if both the above condition is fail it print the message " The number is Zero"

7 0

3 years ago

Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program

Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

.data

sourceword:

.word 0xAB

wordmask:

.word 0xCF

operand:

.long 0xAA

.text

.globl _start

_start:

movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)

movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)

xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)

andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)

orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)

xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)

movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)

movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)

movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)

shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)

# 0x000000AA=00000000000000000000000010101010

# =>00000000000000000000010101010000=0x00000550.

rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)

# 0x000000AA=00000000000000000000000010101010

3 =>10100000000000000000000000001010= 0xA000000A.

sarl %ecx # here the count value to shift the bits not mentioned.

# It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.

See more about logic program at brainly.com/question/14970713

#SPJ1

5 0

2 years ago