Answer:
13,33 MIN.
Explanation:
1. Time with Older Computer (OC) = 2 time with New Computer (NC)
2. OC+ NC = 10 MIN.
replacing 1. in 2. OC + OC/2 = 10 min.
1.5 OC =10min
OC=6.66 MIN
NC = 3,33 MIN.
If we replace NC with OC , 3,33 min will take 2 times (6,66 min)
Total Time = 6,66 + 6,66= 13,33 min
Answer:
The format that is used is: PNG
Explanation:
Call by reference.
Hope this helps
Suppose that you have the following definitions:struct time Type struct tourTypen the variable destination of type your type are tourType input(){cout<<"Enter the city, distance and time in hr and min"<>destination.city name;
<h3>What is C++ statements?</h3>
Expression statements. These statements examine an expression for its aspect outcomes or for its go-back value. Null statements. These statements may be supplied in which a declaration is needed with the aid of using the C++ syntax however in which no motion is to be taken.
- #include
- #include
- the use of namespace std;
- struct timeType
- ;
- struct tourType
- ;
- tourType destination;
- tourType input(){
- cout<<"Enter the city, distance and time in hr and min"<>destination.cityName;
- cin>>destination.distance;
- cin>>destination.travelTime.hr;
- cin>>destination.travelTime.min;
- go back destination;
- }
- void display()cityName;
- d.distance = t->distance;
- d.travelTime.hr = t->travelTime.hr;
- d.travelTime.min = t->travelTime.min;">
- int main().
Read more about the variable :
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