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Thepotemich [5.8K]
3 years ago
11

Which factorization is equivalent to this expression?

Mathematics
1 answer:
grigory [225]3 years ago
8 0

Answer:

10(3x+7)

Step-by-step explanation:

we have the expression:

30x + 70

To factor this expression we need to indentify the components that are common in both terms.

At first glance there is nothing in common, but we can notice that 30 and 70 are multiples of 10, that is:

10*3=30\\10*7=70

so we can substitute this into the expression:

10*3x+10*7

and now that we have the common term (the number 10) we can factorize it, that is, take out the common term and include a parentheses:

10(3x+7)

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Basic geometry question plsss
SSSSS [86.1K]

Answer:

x=53

Step-by-step explanation:

pythagoras theorem

a^2 + b^2 =c^2

here a and b are two small sides and c is hypotenuse (longest side)

28^2 + 45^2 = c^2

784 + 2025 =x^2

2809 =x^2

\sqrt{2809} =x

53 =x

7 0
3 years ago
Which expression represents 5 more than one-third y​
Jlenok [28]

<em>*Five more*</em>

+5

<em>*One-third y*</em>

1/3y

D. 1/3y+5

Hope this helps!!

8 0
3 years ago
Read 2 more answers
Madison deposited $18 in a savings account that earns 2.5% simple interest. Which graph represent this scenario
Dmitriy789 [7]
The answer is 7.20 because $18 divided by 2.5% is 7.20
8 0
3 years ago
Read 2 more answers
GIVING 100 POINTS FOR THE FIRST CORRECT ANSWER
Wittaler [7]
Mrs. Walters gets 14.4 miles per gallon.
Mr. Walters gets 15 miles per gallon.
So Mr. Walters car is better because he gets more miles out of one gallon of gas.
360/25=14.4 480/32=15
Stephen can read 90 pages in 6 days witch means he reads 15 pages per day. Which means it will take him 20 days to read a 300 page book.

90/6=15 300/15=20
4 0
3 years ago
Does anybody know the answer to these questions?
san4es73 [151]

Answer:

  1. 625,000 J

  2. 100 J

  4. 5 kg

  5. √5 ≈ 2.236 m/s

Step-by-step explanation:

You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².

To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.

In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.

__

1. KE = (1/2)<em>m</em>v² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J

__

2. KE = (1/2)<em>m</em>v² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J

__

4. KE = (1/2)<em>m</em>v²

  250 J = (1/2)<em>m</em>(10 m/s)² = 50 m²/s²

  (250 kg·m²/s²)/(50 m²/s²) = <em>m</em> = 5 kg

__

5. KE = (1/2)<em>m</em>v²

  2000 kg·m²/s² = (1/2)(800 kg)v²

  (2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²

  v = √5 m/s ≈ 2.236 m/s

7 0
3 years ago
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