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3 years ago

Please help!!!!!!! ,................

Mathematics

1 answer:

gregori [183]3 years ago

3 0

I need help whit this too!

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A 3-ounce serving of tuna fish provides 24 grams of protein. How many grams of protein are in a 19-ounce serving of tuna fish?

Veronika [31]

24/3 is 8, therefore there are 8 grams of protein per ounce of tuna. So 19*8 wld be 152.. there would be 152 grams of protein in a 19 ounce serving.

6 0

3 years ago

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A fair spinner has eight equal sections.

blagie [28]

Answer:

umm im not sure if its correct but do 2 ( the colors ) times how many times it is spun. so there are 6 .

Step-by-step explanation:

4 0

3 years ago

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Please help 8th grade math

wariber [46]

Answer:

$n \geq -\frac{-29}{28}$

Step-by-step explanation:

$-3(1 - 7n) \geq -32 - 8n\\-3 + 21n \geq -32 -8n\\$

+8n +8n

$-3 + 28n \geq -32\\+3 +3\\28n \geq -29\\/28 /28\\n \geq \frac{-29}{28}$

6 0

4 years ago

Anyone... Someone... please.... hElP mE. im getting sick of this online school stuff

Kobotan [32]

Answer:

30,40,50

Step-by-step explanation:

If it is a right triangle then the pythagorean theorum would work

a^2+b^2=c^2

30^2+40^2=50^2

900+1600=2500

2500=2500

this means that 30,40,50 is the right answer

*******extra********

also 30,40,50 is a pythagorean triplet

pythagorean triplets form right angles

this one came from the original triplet of 3,4,5---just multiply by 10

6 0

3 years ago

At a certain high school, 15 students play stringed instruments and

Aleks [24]

Answer:

0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N( $A \cup B$ )' = 5

To find:

The probability that a randomly selected students plays both = ?

Solution:

Total Number of students = N(A)+N(B)+N( $A \cup B$ )' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

$N(A\cap B) =0$

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0$

So, 0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

5 0

3 years ago