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3 years ago

Point A(4, 5) is translated two units left and three units up. What are the new coordinates of point A

Mathematics

1 answer:

Vinvika [58]3 years ago

6 0

Answer:

A': (2, 8)

Step-by-step explanation:

I have attached the work to your problem below.

I hope this helps.

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Which of the following is equivalent to the complex number i^17

Anton [14]

Answer:

Step-by-step explanation:

It’s a repeating pattern.

i² = -1

i³ =(i²)i = (-1)i = -i

i⁴ = i³i = -i² = 1

i⁵ = (i⁴)i = (1)i = i

i⁶ = i⁵i = i² = -1

...

i¹⁷ = i

4 0

3 years ago

Elliot wrote a computer program that randomly generates a number from 2 to 10. If he runs the program twice, what is the probabi

Vikentia [17]

Answer:

StartFraction 16 over 81 EndFraction

Step-by-step explanation:

There are 4 prime numbers from 2 to 10 (2, 3, 5, 7) and 9 numbers from 2 - 10. Total possibilities: 9 * 9 = 81

Prime possibilities: 4 * 4 = 16

Therefore the answer is 16/81 or StartFraction 16 over 81 EndFraction

8 0

3 years ago

Read 2 more answers

An extremely large sink hole has opened up in a field just outside of the city limits. It is difficult to measure across the sin

abruzzese [7]

Triangle ABC and triangle DCE are congruent, so line DE = line AB

Use the cosine rule to find angle ACB
$52.2^{2}= 50^{2}+ 70^{2}-(2*50*70*cos(ACB))$
$2724.84=7400-(7000cos(ACB))$
$2724.84-7400=-7000cos(ACB)$
$-4675.16=-7000cos(ACB)$
$\frac{4675.16}{7000}=cos(ACB)$
$Angle ACB= cos^{-1} ( \frac{4675.16}{7000})$
Angle ACB = 48.1°

5 0

3 years ago

Ella is making 3 batches of banana milkshakes. She needs

AlexFokin [52]

21 times because you need 7/4=1 gallon and 3/4 just for one and 7x3 =21 so need 21/4

3 0

3 years ago

Actual lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy leng

HACTEHA [7]

Solution :

The data is normally distributed.

The standard deviation is 18 days

Here the data is normally distributed and 54 days is 3 days of standard deviation.

Therefore, the percentage of the births that would be $\text{expected to occur}$ within the 54 days of the mean $\text{pregnancy}$ length is given by :

= P( -3 < Z < 3)

= 0.9544

= 95 %

Therefore, about 95% of the births would be $\text{expected to occur}$ within 54 days of the men $\text{pregnancy}$ length.

8 0

3 years ago