Answer: What is your question
Step-by-step explanation:
Not sure what the extra numbers and equation are, but I'll just solve it.*Note* first number and second number isn't really assigned, just shows one of the numbers of the two*
F= first number
S= second number
F+S=78
F-S= 32
Now, you want to eliminate F, so you'll multiply the first equation by -1
-(F+S=78)
F-S=32
-F-S=-78
F-S=32
-2S=-46
S=23
Now plug in the number to one of the equations.
F+23=78
78-23= 55
The two numbers are 55 and 23.
x^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
Answer:
0.436
Step-by-step explanation:
Given that a professor planned to give an examination in a large class on the Monday before Thanksgiving vacation
Some students asked whether he could change the date because so many of their classmates had at least one other exam on that date.
They speculated that at least 40% of the class had this problem.
The professor agreed to poll the class, and if there was convincing evidence that the proportion with at least one other exam on that date was greater than .40, he would change the date.
No of students in total = 250
Reported they had another exam = 109
proportion of the class reported that they had another exam on the date
=