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3 years ago

What does Juliet do after worrying about whether the potion will work?

Mathematics

1 answer:

galina1969 [7]3 years ago

8 0

Answer:

tdyt8ugt77r6r5etstdd56d6e6d5s5e5e5e6tdufycydycycycycycyxtztxyvib>

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Evaluate the summation of negative 5 n minus 1, from n equals 3 to 12..

NARA [144]

The summation of negative 5 n minus 1, from n equals 3 to 12 can be expressed as

n = 3/12

substitute the value of n to the equatio

-5n – 1

-5( 3/12 ) -1

-9/4

5 0

3 years ago

What’s the distance for someone that drove 60 miles for 12 hours

Colt1911 [192]

Answer:

720 miles.

Step-by-step explanation:

Going 60 miles per hour for 12 hours would amount to driving 720 miles in total.

3 0

3 years ago

Please help! Thanks in advance.

alukav5142 [94]

In this problem, we need to plug in the given x values for $f(x)=0$ and find a and b.

When we plug in 1, we get: $2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0$

Simplify:
$2 - 5 - 14 + a + b = 0$
$- 17 + a + b = 0$
$a + b = 17$

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
$2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0$
$512 - 320 - 224 + 4a + b = 0$
$- 32 + 4a + b = 0$
$4a + b = 32$

Now we have our second one. We can combine them:
$a + b = 17 \\ 4a + b = 32$

I use elimination method which is easier here.

Multiply the top equation by -1: $- a - b = - 17 \\ 4a + b = 32$

Add them up:
$3a = 15$

Simplify:
$a = 5$

Now we have a, we can plug in one of those equations to find b:
$5 + b = 17$
$b = 17 - 5$
$b = 12$

So, the answers are $a=5$ and $b=12$ .

6 0

3 years ago

Identify The degree of each monomial

vesna_86 [32]

If a polynomial has more than one variable, then thedegree of that monomial is the sum of the exponents of those variables. In this polynomial, 24xyz, thedegree is 3 because the sum of degrees of x, y and z is 1 + 1 + 1 = 3. hope this helps :)

6 0

3 years ago

Ex 2.8 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1

harkovskaia [24]

$y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\
y''(0)=20\cdot0^3=0$

The value of the second derivative for $x=0$ is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of $5x^4$ is always positive for $x\in\mathbb{R}\setminus \{0\}$ . That means at $x=0$ there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval $[-2,1]$ .
The function $y$ is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

$y_{max}=y(1)=1^5-3=-2$

4 0

3 years ago