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kondor19780726 [428]
3 years ago
8

Which figure has a greater area?19 ft16.4 ft.15 ft16.1 ft​

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

green triangle

Step-by-step explanation:

The green triangle has an area of

A = 1/2 bh

A = 1/2 (15) * 19

A =142.5 ft^2

The blue triangle has an area of

A = 1/2 bh

A = 1/2(16.1) (16.4)

A =132.02 ft^2

The green triangle has a greater area

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Slope and y-intercept form from a table
dsp73

Answer:

The y-intercept is 3

Gradient: 4

11-3= 8

2-0= 2

8/2= 4

Hope this helped!

 

4 0
2 years ago
A rectangle has a length of (x+10) centimeters and a width of x centimeters. If the perimeter is 32 centimeters, what is the len
I am Lyosha [343]

Given:

Length of rectangle = (x+10) cm

Width of the rectangle = x cm

Perimeter = 32 cm

To find:

The length of the rectangle.

Solution:

We know that,

Perimeter=2(l+w)

Where, l is length and w is width.

Substituting the values, we get

32=2((x+10)+x)

32=2(2x+10)

32=4x+20

Subtract 20 from both sides.

32-20=4x

12=4x

Divide both sides by

3=x

So, the length is

3+10=13

Therefore, the length of the rectangle is 13 cm.

7 0
2 years ago
Solve for c.<br><br> a(c−b)=d
tatiyna

Answer:

c= ab + d/ a

Step-by-step explanation:

Let's solve for c.

a(c-b)=d

Step 1: Add ab to both sides.

-ab + ac + ab = d+ ab

ac = ab + d

Step 2: Divide both sides by a.

ac / a = ab + d / a

c = ab + d/ a

Answer:

c= ab + d/ a

Hope this helps ☝️☝☝

3 0
3 years ago
Write the nth term of the following sequence in terms of the first term of the sequence.
vovikov84 [41]

Givens

Sequence 2, - 4, 8, -16, 32 ....

First term = a = 2

Problem

Find the nth term

tn = (-1 )^(n -1) * (a)^n answer or

tn = (-1)^(n - 1) * 2^n

where a is defined as the first term (it usually is given that designation).

Try a few to make sure the formula is correct

<em>n = 1</em>

t1 = (-1)^(1 - 1) * 2^1

t1 = (-1)^0 * 2

t1 = 1 * 2 = 2

<em>n =2</em>

t2 = (-1)^(2 - 1) * 2^2 = (-1)^1 * 4 = -4

6 0
2 years ago
A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If
jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

V=\frac{4}{3}\pi r^3, where r represents radius of sphere.

We know that radius is half the diameter, so radius of each candle will be \frac{15}{2}=7.5 cm.

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot (7.5\text{ cm})^3

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot 421.875\text{ cm}^3

\text{Volume of one candle}=1766.25\text{ cm}^3

Now we will divide 70,650 cubic cm of wax by volume of one candle.

\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}

\text{Number of candles}=\frac{70,650}{1766.25}

\text{Number of candles}=40

Therefore, 40 candles can be made from 70,650 cubic cm of wax.

8 0
3 years ago
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