All categories

3 years ago

Please answer quickly!

Mathematics

1 answer:

Damm [24]3 years ago

6 0

Answer:

2.57 or 2.5703939893007399

Hope this helped have a good one! :)

You might be interested in

Every _____ tessellates

Charra [1.4K]

Answer:

Every <u>hexagon </u>tessellates.

Step-by-step explanation:

Hexagons always tessellates when perfectly combined and aligned especially when the x sides and the y sides are parallel to each other.

4 0

3 years ago

The brand manager for a brand toothpaste must plan a campaign designed to increase brand recognition. He wants to first determin

bulgar [2K]

We need to find out how many adults must the brand manager survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage.

From the given data we know that our confidence level is 90%. From Standard Normal Table we know that the critical level at 90% confidence level is 1.645. In other words, $Z_{Critical}=1.645$ .

We also know that E=5% or E=0.05

Also, since, $\hat{p}$ is not given, we will assume that $\hat{p}$ =0.5. This is because, the formula that we use will have $\hat{p}(1-\hat{p})$ in the expression and that will be maximum only when $\hat{p}$ =0.5. (For any other value of $\hat{p}$ , we will get a value less than 0.25. For example if, $\hat{p}$ is 0.4, then $1-\hat{p}=0.6$ and thus, $\hat{p}(1-\hat{p})=0.24$ .).

We will now use the formula

$n=(\frac{Z_{Critical}}{E})^2\hat{p}(1-\hat{p})$

We will now substitute all the data that we have and we will get

$n=(\frac{1.645}{0.05})^2\times0.5(1-0.5)$

$n=(32.9)^2\times0.25$

$n=270.6025$

which can approximated to n=271.

So, the brand manager needs a sample size of 271

3 0

3 years ago

Work out the product of

nignag [31]

That will be 4/4/7 hope this helps

5 0

3 years ago

PLEASE HELPPPPP!!!!!!!!! (show work if you can)

Kryger [21]

Answer:

$180x^4y^3z^2$

Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

$LCM(12,18,30)=180$

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term ( $x$ , $y$ , and $z$ ). The largest term of $x$ is $x^4$ in the first polynomial, so we'll take exactly that for our $x$ term in the LCM, absolutely nothing more. Similarly, the largest term of $y$ in any of the three polynomials is $y^3$ (also in the first polynomial) and the largest $z$ term in any of the three polynomials is $z^2$ in the second polynomial. Thus, the LCM of all our polynomials is: