Answer:
There are
five dollar bills and
ten dollar bills.
Step-by-step explanation:
Given:
Selling price of bicycle
.
The friend gave
five dollar bills and
ten dollar bills.
Total number of bills
.
To find: Number of five dollar bills and ten dollar bills the friend gave.
Solution:
The friend gave
five dollar bills and
ten dollar bills and the friend gave
bills in all.
So,
.

Selling price of bicycle
.
So, 
Putting the value of
from equation
in equation
.







Now, putting the value of
in equation
.


Hence, there are
five dollar bills and
ten dollar bills.
<span>A
and B must be invertible, we have UA=B, since A is invertible. A^-1 exists, by multiplying with A^-1,
we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix)
and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>
Answer:
38
Step-by-step explanation:
Since Oliver ran 23 fewer laps, you would use subtraction.
So you do 61-23=38
Hope this helps!!
Let me know if you are confused.
(2/3)(30)=20
30+20=50=(x/5)
(50*5)=x=250
hope this helps
The line would be called the median. The definition of '<span>A line connecting a vertex of a scalene triangle with the midpoint of the opposite side' pertains to the median. There are three medians that connect the scalene triangle. </span>