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fiasKO [112]
3 years ago
7

Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bub

ble gum nested at the botta
of the cone. The radius of the snow cone is 2 inches, and the height of the cone is 3 inches. If the diameter of the bubble gum is 0.5 inches, which of the following
can be used to calculate the volume of the cone that can be filled with flavored ice?
03(3.14)(23)(3) - (3.14(0.253)
03 (3.14)(33(2) - (3.140.253
0313.141(23)(3) - (3.1410:53
03 (3.1416331(2) - (3.14)(0.5%)
Mathematics
1 answer:
cupoosta [38]3 years ago
3 0

Let us first note down all the information's that are given in the question.

Radius of the snow cone = 4 inches

Height of the snow cone = 6 inches

Diameter of the bubble gum = 0.8 inches

Then

Radius of the bubble gum = 0.4 inches

Now

Volume of the come = 1/3 * pi * (radius)2 * height

                                = 1/3 * 3.14 * (4) ^2 * 6

                                = 3.14 * 16 * 2

                                = 100.48 cubic inches

Again  

Volume of the sphere = (4/3) * pi * (radius)^3

                                  = (4/3) * 3.14 * (0.4)^3

                                  = (4/3) * 3.14 * 0.064

                                  = 0.2679 cubic inches

Volume of the cone

that can be filled with flavored ice = 100.48 - 0.27

                                                     = 100.21 cubic inches

The correct option among all the options that are given in the question is option "d".

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Inverse Trigonometry solve the questions below
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Answer:

1. θ = 34.85°

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