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jek_recluse [69]

4 years ago

10

Barbara sells iced tea for $1.49 per bottle and water for $1.25 per bottle. She wrote an equation to find the number of bottles

she needs to sell to earn $100.

1 answer:

taurus [48]4 years ago

7 0

Answer:

the answer is b (Barbara's equation did not consider the number of bottles of iced tea.)

Step-by-step explanation:

its math i did years ago its like simple math for me. trust me i know its right

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1) Solve by using the perfect squares method. x2 + 8x + 16 = 0

Bond [772]

1)
$x^2+8x+16=0 \\
(x+4)^2=0 \\
x+4=0 \\
\boxed{x=-4}$

2)
$x^2-5x-6=0 \\
x^2-6x+x-6=0 \\
x(x-6)+1(x-6)=0 \\
(x+1)(x-6)=0 \\
x+1=0 \ \lor \ x-6=0 \\
x=-1 \ \lor \ x=6 \\
\boxed{x=-1 \hbox{ or } x=6}$

3)
$\hbox{a perfect square:} \\ (x-a)^2=x^2-2xa+a^2 \\ \\ 2xa=20x \\ a=\frac{20x}{2x} \\ a=10 \\ \\ a^2=10^2=100 \\ \\ \hbox{the expression:} \\ x^2-20x+100 \\ \\ \boxed{\hbox{100 should be added to the expression}}$

4)
$x^2+8x-8=0 \\ \\
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\sqrt{\Delta}=\sqrt{96}=\sqrt{16 \times6}=4\sqrt{6} \\ \\
x=\frac{-b \pm \sqrt{\Delta}}{2a}=\frac{-8 \pm 4\sqrt{6}}{2 \times 1}=\frac{2(-4 \pm 2\sqrt{6})}{2}=-4 \pm 2\sqrt{6} \\
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5)
$2x^2+12x=0 \\
2x(x+6)=0 \\
2x=0 \ \lor \ x+6=0 \\
x=0 \ \lor \ x=-6 \\
\boxed{x=-6 \hbox{ or } x=0}$

6)
$2x^2-2x-1=0 \\ \\
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7)
$x^2-x+2=0 \\ \\
a=1 \\ b=-1 \\ c=2 \\
\Delta=b^2-4ac=(-1)^2-4 \times 1 \times 2=1-8=-7 \\ \\
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8)
$3x^2-6x+1=0 \\ \\
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9)
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10)
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Step-by-step explanation:

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Answer:

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Vadim26 [7]

Answer: 0.267

Step-by-step explanation:

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