<span>Un cubo tiene seis caras.
</span>Las dos imágenes ayudan a explicar. Uno de los cubos es un cubo transparente.<span> Por otro cubo es cubo hueco que se ha desplegado.</span> E<span>spero que esto ayude</span>
We know, sum of all the angles in a triangle is equal to 180 degree
So, 90 + 2x + 3x = 180
5x = 180-90
x = 90/5
x = 18
∠ANB = 2x = 2(18) = 36
∠BNC = 3x = 3(18) = 54
Hope this helps!
7 and 4
7+4=11
7•4=28
Hope it helps
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
{[(8 - 3) * 2] + [(5 * 6) - 5]} / 5 =
= {[2 * 8 + 2 * (-3)] + 30 - 5} / 5 =
= [(16 - 6) + 25] / 5 =
= (10 + 25) / 5 =
= 35 / 5 =
= 7
Brackets make it look complex but it's not that bad at all :)
