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Deffense [45]
3 years ago
11

Point C ∈

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

  • AC: 11 cm
  • CB: 22 cm

Step-by-step explanation:

<u>Given</u>:

  AC + CB = 33

  CB = 2AC

<u>Find</u>:

  AC, CB

<u>Solution</u>:

Using substitution, we have ...

  AC +2AC = 33

  AC = 33/3 = 11

  CB = 2·11 = 22

AC = 11 cm; CB = 22 cm.

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photoshop1234 [79]
7-2( \frac{8}{2} )+9 =

Remove parentheses:

7-2* \frac{8}{2} +9 =

7 - 2 * 4 + 9 =

7 - 8 + 9 =

= -1 + 9

= 8

hope this helps!



6 0
3 years ago
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

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3 years ago
EASY BRAINLIEST PLEASE HELP!!
Galina-37 [17]

Answer: B

Step-by-step explanation: its B

8 0
3 years ago
Read 2 more answers
PLEASE HELP! HURRY! since its 2 questions, ILL GIVE MORE POINTS!
VARVARA [1.3K]

A. m = 0 || This is incorrect, because m being equal to 0 is a solution in and of itself.

B. m = m || This is incorrect, because m being equal to itself means that there are an infinite number of solutions.

C. 2m + 1 = m - 2 | m = -3 || This is incorrect, because m can be solved for and has a solution.

D. m + 4 = m - 4 | 4 = -4 || This is correct because 4 is not equal to -4, and thus there is no solution.

Hope this helps!! :)

6 0
3 years ago
Find the value of each variable
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Answer:

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