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Amanda [17]
3 years ago
5

Which interval contains a local minimum for the graphed function?

Mathematics
2 answers:
andreev551 [17]3 years ago
8 0
Use photomath bc that app always helps
SSSSS [86.1K]3 years ago
4 0

Answer:[2.5,4]. D

Step-by-step explanation:

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Y = f(x) = 2x<br> Find f(x) when x = 2.<br> Enter the correct answer.
sdas [7]

Answer:

<h2>f(x) = 4</h2>

Step-by-step explanation:

f(x) = 2x

When x = 2

Substitute the value of x into f(x)

That's

f(2) = 2(2)

= 4

Hope this helps you

6 0
3 years ago
Read 2 more answers
Each of the following tables defines a relationship between an input x and an output y. Which of the relationship respresent fun
sveticcg [70]

Answer:

wat

Step-by-step explanation:

nose

6 0
3 years ago
Find radius of the sphere from the following volume
nordsb [41]
Can you send a picture by chance?
3 0
2 years ago
For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0
3 years ago
If f(x)= x2+2x-10, what id f(-2)
Sindrei [870]
The answer is -18. Hope this helps.
6 0
3 years ago
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